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# Binary Search Program using methods – array- Class 12 Computer Science

Program to perform binary search, values input by the user using Scanner class. Binary Search can do only in sorted arrays. So a method for Sorting bubble Sort technique , then in the sorted array key is searched by BinarySearch method.

Usually we do by initializing the array value. Here each process defined in user defined methods.

``````import java.util.*;
public class Userdefined
{

static void BubbleSort(int num[])  //Sorting
{
int len=num.length;
int i,j, temp;
for(i=0;i<len;i++)
{
for( j=0;j<len-i-1;j++)
{
if(num[j]>num[j+1])
{
temp=num[j];
num[j]=num[j+1];
num[j+1]=temp;

}
}
}
//   System.out.println("Sorted Elements:");
for(int k=0;k<len;k++)
System.out.print(num[k]+"\t");
System.out.println();
}
static void BinSearch(int num[],int k)  //Binary Search
{
int l=0,u=num.length-1;
int m=0, found=0;
while(l<=u)
{
m= (l+u)/2;
if( k > num[m])
l =m+1;
else if( k< num[m])
u=m-1;
else
{
found =1;
break;

}

}
if(found==1)
System.out.println(" Element Present at"+" "+ (m+1) +" " +"after sorting");

else
System.out.println("Not Present");
}
public static void main(String [] args)
{
Scanner sc=new Scanner(System.in);
System.out.println( "Enter the total number of elements in the array:");
int n=sc.nextInt();
int a[]=new int[n];
System.out.println( "Enter the elements:");
for(int i=0;i<n;i++)
{
a[i]=sc.nextInt();
}
System.out.println("Entered Elements");
for(int i=0;i<n;i++)
{

System.out.print(a[i]+"\t");

}
System.out.println();
System.out.println("Elements should be sorted before Binary Search .....\n                                                                                                                                         ..Sorted Elements....");
BubbleSort(a);                         //invoking BubbleSort ()

System.out.println("Binary Search \n");

System.out.println("Enter element to search");
int ky=sc.nextInt();
BinSearch(a, ky); // invoking Binary search method
}

}``````

Output:

Enter the total number of elements in the array:
5
Enter the elements:
54
12
78
1
6
Entered Elements
54 12 78 1 6
Elements should be sorted before Binary Search …..
…Sorted Elements….
1 6 12 54 78
Binary Search

Enter element to search
12
Element Present at 3 after sorting

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# Q & A session – only 10 questions from Methods chapter & related

Dear Students, It is a simple Q & A session of 10 questions. related to Methods and simple concepts. You can answer in the comment box !!!

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# 2D Array – ISC 12th Computer- SOLVED SPECIMEN QUESTION PAPER – 2021

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Write a program to declare a square matrix M [ ] [ ] of order ‘N’ where ‘N’ must be greater than 3 and less than 10. Allow the user to accept three different characters from the keyboard and fill the array according to the instruction given below:

(i) Fill the four corners of the square matrix by character 1.
(ii) Fill the boundary elements of the matrix (except the four corners) by character 2.
(iii) Fill the non-boundary elements of the matrix by character 3.

Test your program with the following data and some random data:

Example 1:
INPUT: N = 4
FIRST CHARACTER: @
SECOND CHARACTER: ?
THIRD CHARACTER: #

OUTPUT:
@ ? ? @
? # # ?
? # # ?
@ ? ? @

Example 2: INPUT: N = 5
FIRST CHARACTER: A
SECOND CHARACTER: C
THIRD CHARACTER: X

OUTPUT:
A C C C A
C X X X C
C X X X C
C X X X C
A C C C A

Example 3: INPUT: N = 15
OUTPUT: SIZE OUT OF RANGE

``````import java.util.*;
class matRIX
{
public static void main(String args[])
{
Scanner sc=new Scanner(System.in);
System.out.println("Enter no.of rows M of a square matrix:");
int m=sc.nextInt();
char mat[][] = new char[m][m];
System.out.println("Enter corner elements - 1st character:");
char ch1=sc.next().charAt(0);
System.out.println("Enter boundary except corner elements - 2ndcharacter:");
char ch2=sc.next().charAt(0);
System.out.println("Enter  non boundary  - 3rdcharacter:");
char ch3=sc.next().charAt(0);

for(int i=0; i<m; i++)
{
for(int j=0; j<m;j++)
{
//fill corners with char 1
if( (i==0||i==m-1) && (j==0 || j==m-1))
mat[i][j]=ch1;
//fill non-corner boundary elememts with char 2
else if(i==0 || j==0 || i==m-1 || j==m-1)
mat[i][j]=ch2;
//fill rest with char 3
else
mat[i][j]=ch3;
}
}

//print the array
System.out.println("");
for(int i=0; i<m; i++)
{
for(int j=0; j<m; j++)
{
System.out.print(mat[i][j] + "\t");
}
System.out.println();
}

}
}``````

OUTPUT:

Enter no.of rows M of a square matrix:
5
Enter corner elements – 1st character:
@
Enter boundary except corner elements – 2ndcharacter:
?
Enter non boundary – 3rdcharacter:
#

@ ? ? ? @
? # # # ?
? # # # ?
? # # # ?
@ ? ? ? @

# Converting first character into UpperCase

Write a program to accept a sentence and check whether it is terminated by ‘.’ or ‘? ‘ or ‘!’ . Display the words using default delimiter (space) and the first character of each word should be converted into Upper Case.

Sample Input :

converting first character.

Sample Output:

converting Converting
first First
character Character

``````import java.util.*;
class strDec
{
public static String firstLetter(String wrd)
{
String res="";char ch2=' ';
int l=wrd.length();
for(int i=1;i<l;i++)
{
char ch1=wrd.charAt(i);
ch2=wrd.charAt(0);
if(Character.isLowerCase(ch2))
{
ch2 =Character.toUpperCase(ch2);

}
//System.out.println(ch1);
res=res +ch1;

}
res=ch2+res;
return res;
//System.out.println(res);
}
public static void main(String args[])

{   strDec strd=new strDec();
String str;
Scanner sc=new Scanner(System.in);
System.out.println("Enter a sentence:");
str=sc.nextLine();
int l=str.length();
char c=str.charAt(l-1);

if(c=='.'||c=='?'||c=='!')
{
StringTokenizer st=new StringTokenizer( str, " .?!");
int n=st.countTokens();
String wrd[]=new String [n];

String ch[]=new String[n];

for(int i=0;i<n;i++){
wrd[i]=st.nextToken();
ch[i]=firstLetter(wrd[i]);
System.out.println(wrd[i] + "    "+ch[i]+" " );
}

}

else
{
System.out.println("Enter a sentence terminated with . or ? or ! :");
}

}
}
``````

Output:

Enter a sentence:
the sky is the limit.
the The
sky Sky
is Is
the The
limit Limit

# ISC Computer Science Practical – Previous Year 2020 – Solved Paper – Matrix program

Write a program to declare a matrix A[][]of order ( M*N) where ‘M’ is the number of rows and ‘N’ is the number of columns such that the value of “M’ must be greater than 0 and less than 10 and the value of ‘N’ must be greater than 2 and less than 6. Allow the user to input digits (0-7) only at each location, such that each row represents an octal number.

Example:

```231(decimal equivalent of 1st row=153 i.e. 2*8² +3*8¹ +1*8⁰)
405(decimal equivalent of 1st row=261 i.e. 4*8¹ +0*8¹ +5*8⁰)
156(decimal equivalent of 1st row=110 i.e. 1*8² +5*8¹ +6*8⁰)

Perform the following tasks on the matrix:```
• Display the original matrix.
• Calculate the decimal equivalent for each row and display as per the format given below.
```Example 1:
Input:
M=1
N=3
ENTER ELEMENTS FOR ROW 1: 1   4  4
Output:
FILLED MATRIX   DECIMAL EQUIVALENT
1  4  4                100

Example 2:
Input:
M=3
N=4
ENTER ELEMENTS FOR ROW 1: 1 1 3 7
ENTER ELEMENTS FOR ROW 2: 2 1 0 6
ENTER ELEMENTS FOR ROW 3: 0 2 4 5
Output:
FILLED MATRIX   DECIMAL EQUIVALENT
1 1 3 7         607
2 1 0 6         1094
0 2 4 5         165

Example 3:
Input:
ENTER ROW SIZE  M=3
ENTER COLUMN SIZE N=9
Output:OUT OF RANGE```
``````import java.util.*;
class mat
{
public static void main(String args[])
{
Scanner sc=new Scanner(System.in);
System.out.println("Enter no.of rows M ");
int m=sc.nextInt();
System.out.println("Enter no.of rows N ");
int n= sc.nextInt();
int flag=0,pow=0;
int mat[][]=new int[m][n];
if((m>0 && m< 10 )&&(n>2 && n<6))          //M >0 AND <10  && N>2 AND <6
{
for(int i=0;i<m;i++)
{System.out.print("Enter elements for row "+(i+1)+":");
for(int j=0;j<n;j++)
{
mat[i][j]=sc.nextInt();
if(mat[i][j] < 0 ||   mat[i][j]>7)     //ALLOW THE USER TO INPUT ONLY FROM 0 TO 7 (OCTAL)
{
flag=1;
System.out.println("INPUT DIGITS (0 -7) ONLY AT EACH LOCATION");
System.exit(1);

}

}

}
}
if(flag==0)
{
System.out.println("FILLED MATRIX \t DECIMAL EQUIVALENT");
for(int i=0;i<m;i++)
{
int r=0,sum=0;
for(int j=n-1;j>=0;j--)
{
pow=((int)Math.pow(8,r++));
sum=sum+(mat[i][j]*pow);

}

for(int k=0;k<n;k++)
{
System.out.print(mat[i][k]+ " " );
}
System.out.print("\t\t \t" +sum);
System.out.println();
}
}

else
System.out.println("Enter valid range");
}
}

``````

OUTPUT:

Enter no.of rows M
3
Enter no.of rows N
3
Enter elements for row 1:2 3 1
Enter elements for row 2:4 0 5
Enter elements for row 3:1 5 6

FILLED MATRIX DECIMAL EQUIVALENT
2 3 1 153
4 0 5 261
1 5 6 110

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# to print possible combinations of numbers (234, 243,324,342,etc)

``import java.util.*;class permutationDigits{int count = 0;void input() { Scanner sc = new Scanner(System.in); System.out.print("Enter a digit: "); int a= sc.nextInt(); String s=String.valueOf(a);  //converting int into stringSystem.out.println("The Anagrams are : "); compute("",s); System.out.println("Total Number of Anagrams = "+count); } void compute(String s1, String s2) { if(s2.length()<=1) { count++; System.out.println(s1+s2); } else { for(int i=0; i<s2.length(); i++) { String a = s2.substring(i, i+1); String b = s2.substring(0, i); String c = s2.substring(i+1); compute(s1+a, b+c); } } } public static void main(String args[]){ permutationDigits ob=new permutationDigits(); ob.input(); }}``

Output:

Enter a digit: 234
The Anagrams are :
234
243
324
342
423
432
Total Number of Anagrams = 6

# To print Anagrams (eg: TOP,TPO,POT, etc..)

``import java.util.*;class anagramsWord{int count = 0;void input() { Scanner sc = new Scanner(System.in); System.out.print("Enter a word : "); String s = sc.next(); System.out.println("The Anagrams are : "); compute("",s); System.out.println("Total NO. of Anagrams = "+count); } void compute(String s1, String s2) { if(s2.length()<=1) { count++; // no of combination words System.out.println(s1+s2); } else { for(int i=0; i<s2.length(); i++) { String a = s2.substring(i, i+1); String b = s2.substring(0, i); String c = s2.substring(i+1); compute(s1+a, b+c); // recursive method } } } public static void main(String args[])throws Exception { anagramsWord ob=new anagramsWord(); ob.input(); }}``

Output:

Enter a word : TOP
The Anagrams are :
TOP
TPO
OTP
OPT
PTO
POT
Total NO. of Anagrams = 6

# Printing possible combinations of 4 digit number

```import java.util.*;
public class Combinations
{
public static void main(String[] args)
{
int[] a = { 1, 5, 3, 6 };
for (int w = 0; w < 4; w++)
{
for (int x = 0; x < 4; x++)
{
for (int y = 0; y <4; y++)
{
for (int z = 0; z < 4; z++)
{
if (w!=x && x != y && y != z && z != x)
{
System.out.println(a[w] + ""+a[x] + "" + a[y] + "" + a[z]);
}
}
}
}
}
}
}
```

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5163 continue….